14:I[70017,["/_next/static/immutable/chunks/2gtpnylaz50zo.js","/_next/static/immutable/chunks/22kg_k_j3c_ao.js","/_next/static/immutable/chunks/3s-qhi50ildb6.js"],""] 15:I[16632,["/_next/static/immutable/chunks/2gtpnylaz50zo.js","/_next/static/immutable/chunks/22kg_k_j3c_ao.js","/_next/static/immutable/chunks/3s-qhi50ildb6.js"],"default"] 16:I[3261,["/_next/static/immutable/chunks/2gtpnylaz50zo.js","/_next/static/immutable/chunks/22kg_k_j3c_ao.js","/_next/static/immutable/chunks/3s-qhi50ildb6.js"],"default"] 17:I[44578,["/_next/static/immutable/chunks/2gtpnylaz50zo.js","/_next/static/immutable/chunks/22kg_k_j3c_ao.js","/_next/static/immutable/chunks/3s-qhi50ildb6.js"],"default"] 18:T19f2,{ "consigne": "Choisis d'abord la relation, puis calcule chaque valeur avec son unité. Ici, m est la masse de soluté et V le volume de solution.", "donnees": [ { "cle": "litre", "tex": "1\\ \\text{L} = 1\\,000\\ \\text{mL}" } ], "questions": [ { "enonce": "Quelle ligne donne correctement les trois formes de la relation entre cₘ, m et V ?", "donnees": [], "choix": [ "c_m = m \\times V\\quad ; \\quad m = \\dfrac{c_m}{V}\\quad ; \\quad V = \\dfrac{c_m}{m}", "c_m = \\dfrac{m}{V}\\quad ; \\quad m = c_m \\times V\\quad ; \\quad V = \\dfrac{m}{c_m}", "c_m = \\dfrac{V}{m}\\quad ; \\quad m = \\dfrac{V}{c_m}\\quad ; \\quad V = m \\times c_m", "c_m = \\dfrac{m}{V}\\quad ; \\quad m = \\dfrac{V}{c_m}\\quad ; \\quad V = c_m \\times m" ], "bonne": 1, "explication": "La concentration en masse est la masse de soluté par litre de solution. On isole ensuite la grandeur cherchée." }, { "enonce": "On prépare 0,50 L de solution avec 30 g de sucre. Quelle est la concentration en masse ?", "donnees": [], "reponse": 60, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "explication": "cₘ = 30 ÷ 0,50 = 60 g.L⁻¹. Un litre entier de cette solution contiendrait donc 60 g de sucre." }, { "enonce": "On dissout 5,0 g de sel dans de l'eau, puis on complète jusqu'à obtenir 2,0 L de solution. Quelle est la concentration en masse ?", "donnees": [], "reponse": 2.5, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "explication": "cₘ = 5,0 ÷ 2,0 = 2,5 g.L⁻¹." }, { "enonce": "On prépare 0,25 L de solution avec 12 g de sulfate de cuivre. Quelle est la concentration en masse ?", "donnees": [], "reponse": 48, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "explication": "cₘ = 12 ÷ 0,25 = 48 g.L⁻¹." }, { "enonce": "On dissout 4,0 g de soluté, puis on complète jusqu'à obtenir 200 mL de solution. Quelle est la concentration en masse ?", "donnees": ["litre"], "reponse": 20, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "aide": "Pour obtenir des g.L⁻¹, le volume doit être en litres.", "explication": "200 mL = 0,200 L, donc cₘ = 4,0 ÷ 0,200 = 20 g.L⁻¹." }, { "enonce": "Une solution a une concentration en masse de 20 g.L⁻¹. Quelle masse de soluté contiennent 0,50 L de cette solution ?", "donnees": [], "reponse": 10, "tolerancePct": 2, "unite": "g", "aide": "Tu cherches une masse, donc isole m dans la relation.", "explication": "m = 20 × 0,50 = 10 g." }, { "enonce": "Une solution est à 30 g.L⁻¹. Quel volume faut-il en prélever pour avoir 15 g de soluté ?", "donnees": [], "reponse": 0.5, "tolerancePct": 2, "unite": "L", "aide": "Tu cherches un volume, donc isole V dans la relation.", "explication": "V = 15 ÷ 30 = 0,50 L." }, { "enonce": "On prépare 0,40 L de solution avec 2,0 g de colorant. Quelle est la concentration en masse ?", "donnees": [], "reponse": 5, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "explication": "cₘ = 2,0 ÷ 0,40 = 5,0 g.L⁻¹." }, { "enonce": "Une solution est à 50 g.L⁻¹. Quelle masse de soluté contiennent 0,25 L ?", "donnees": [], "reponse": 12.5, "tolerancePct": 2, "unite": "g", "explication": "m = 50 × 0,25 = 12,5 g." }, { "enonce": "On prépare 250 mL de solution avec 5,0 g de glucose. Quelle est la concentration en masse ?", "donnees": ["litre"], "reponse": 20, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "explication": "250 mL = 0,250 L, donc cₘ = 5,0 ÷ 0,250 = 20 g.L⁻¹." }, { "enonce": "On prépare 100 mL de solution avec 1,5 g de sel. Quelle est la concentration en masse ?", "donnees": ["litre"], "reponse": 15, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "explication": "100 mL = 0,100 L, donc cₘ = 1,5 ÷ 0,100 = 15 g.L⁻¹." }, { "enonce": "Une eau sucrée est à 40 g.L⁻¹. Quelle masse de sucre contiennent 1,5 L ?", "donnees": [], "reponse": 60, "tolerancePct": 2, "unite": "g", "explication": "m = 40 × 1,5 = 60 g." }, { "enonce": "Une solution est à 8,0 g.L⁻¹. Quelle masse de soluté contiennent 250 mL ?", "donnees": ["litre"], "reponse": 2, "tolerancePct": 2, "unite": "g", "explication": "250 mL = 0,250 L, donc m = 8,0 × 0,250 = 2,0 g." }, { "enonce": "Quel volume de solution à 25 g.L⁻¹ contient 10 g de soluté ?", "donnees": [], "reponse": 0.4, "tolerancePct": 2, "unite": "L", "explication": "V = 10 ÷ 25 = 0,40 L." }, { "enonce": "Quelle masse de sel faut-il peser pour préparer 200 mL de solution à 9,0 g.L⁻¹ ?", "donnees": ["litre"], "reponse": 1.8, "tolerancePct": 2, "unite": "g", "explication": "200 mL = 0,200 L, donc m = 9,0 × 0,200 = 1,8 g." }, { "enonce": "On prépare 50,0 mL de solution avec 2,0 g de sulfate de cuivre. Quelle est la concentration en masse ?", "donnees": ["litre"], "reponse": 40, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "explication": "50,0 mL = 0,0500 L, donc cₘ = 2,0 ÷ 0,0500 = 40 g.L⁻¹." }, { "enonce": "Une eau minérale contient 80 mg.L⁻¹ de magnésium. Quelle masse de magnésium y a-t-il dans 0,50 L de cette eau ? Réponds en mg.", "donnees": [], "reponse": 40, "tolerancePct": 2, "unite": "mg", "explication": "m = 80 × 0,50 = 40 mg. La concentration est en mg.L⁻¹, donc la masse est en mg." }, { "enonce": "On prépare 20 mL de solution avec 0,60 g de soluté. Quelle est la concentration en masse ?", "donnees": ["litre"], "reponse": 30, "tolerancePct": 2, "unite": "g.L⁻¹|g/L", "aide": "Convertis d'abord le volume en litres.", "explication": "20 mL = 0,020 L, donc cₘ = 0,60 ÷ 0,020 = 30 g.L⁻¹." }, { "enonce": "Quel volume d'une solution à 50 g.L⁻¹ faut-il prélever pour avoir 2,0 g de soluté ? Réponds en mL.", "donnees": ["litre"], "reponse": 40, "tolerancePct": 2, "unite": "mL", "aide": "Le calcul donne un volume en litres. Convertis-le ensuite en mL.", "explication": "V = 2,0 ÷ 50 = 0,040 L, soit 40 mL." } ] } 19:T168d,

c_m = m \times V\quad ; \quad m = \dfrac{c_m}{V}\quad ; \quad V = \dfrac{c_m}{m}

1a:T168b,

c_m = \dfrac{m}{V}\quad ; \quad m = c_m \times V\quad ; \quad V = \dfrac{m}{c_m}

1b:T168b,

c_m = \dfrac{V}{m}\quad ; \quad m = \dfrac{V}{c_m}\quad ; \quad V = m \times c_m

1c:T1672,

c_m = \dfrac{m}{V}\quad ; \quad m = \dfrac{V}{c_m}\quad ; \quad V = c_m \times m

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1\\ \\text{L} = 1\\,000\\ \\text{mL}

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